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√7-x+5=x help please

Sagot :

x-5=[tex]\sqrt{7-x}[/tex]

Squaring and subtracting 7-x, we get:

[tex]x^2-9x+18=0[/tex]

Factoring, we have:

(x-6)(x-3)=0
So x can be 6 or 3.
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