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please l need help with this system of equation. Solve the system by the method of substitution.
3/2× +3/4y =16
3/4×-y =4
(×,y)=?

Sagot :

Crisforpidn
y = ( 3 / 4 )x - 4 and ( 3 / 2 )x + ( 3 / 4 )y = 16 ;
Then, ( 3 / 2 )x + ( 3 / 4 )[ ( 3 / 4 )x - 4 ] = 16 ;
( 3 / 2 )x + ( 9 / 16 )x - 3 = 16 ;
( 3 / 2 )x + ( 9 / 16 )x = 19 ;
( 24 / 16 )x + ( 9 / 16 )x = 304 / 16 ;
24x + 9x = 304 ;
33x = 304 ;
x = 9.(21);
y = ( 3 / 4 ) × 9.(21) - 4 = 2.90 ;
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