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if a scale map is 1 cm: 15 Km. find the actual distance corresponding to the scale map. 13) 2.5 cm 14) 0.2 cm 15) 15 cm 16) 4.6 cm

Sagot :

Browntown5idn
All you gotta do is multiply the cm by 15,
For 13) you'd do [tex]2.5*15[/tex]
14) [tex]0.2*15[/tex] 
15) [tex]15*15[/tex]
then for 16) [tex]4.6*15[/tex]
Calculistaidn

Let

x-------> distance in the map in cm

y-------> actual distance in Km

we know that

[tex]Scale\ Map=\frac{x}{y} \\ \\ Scale\ Map=\frac{1}{15}\frac{cm}{Km}[/tex]

so

[tex]\frac{x}{y}=\frac{1}{15}[/tex]

[tex]y=15x[/tex] --------> equation [tex]1[/tex]

Part 13) find the actual distance corresponding to the scale map [tex]2.5\ cm[/tex]

In this problem we have

[tex]x=2.5\ cm[/tex]

Substitute the value of x in the equation  [tex]1[/tex] to find the actual distance

[tex]y=15*2.5=37.5\ Km[/tex]

therefore

the answer part 13) is

the actual distance is [tex]37.5\ Km[/tex]

Part 14) find the actual distance corresponding to the scale map [tex]0.2\ cm[/tex]

In this problem we have

[tex]x=0.2\ cm[/tex]

Substitute the value of x in the equation  [tex]1[/tex] to find the actual distance

[tex]y=15*0.2=3\ Km[/tex]

therefore

the answer part 14) is

the actual distance is [tex]3\ Km[/tex]

Part 15) find the actual distance corresponding to the scale map [tex]15\ cm[/tex]

In this problem we have

[tex]x=15\ cm[/tex]

Substitute the value of x in the equation  [tex]1[/tex] to find the actual distance

[tex]y=15*15=225\ Km[/tex]

therefore

the answer part 15) is

the actual distance is [tex]225\ Km[/tex]

Part 16) find the actual distance corresponding to the scale map [tex]4.6\ cm[/tex]

In this problem we have

[tex]x=4.6\ cm[/tex]

Substitute the value of x in the equation  [tex]1[/tex] to find the actual distance

[tex]y=15*4.6=69\ Km[/tex]

therefore

the answer part 16

the actual distance is [tex]69\ Km[/tex]

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