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identify the turning point of the function f(x)=x^2-2x+8 by writing it's equation and vertex form

Sagot :

Panoyinidn
f(x) = x² - 2x + 8
f(x) = x² - 4x + 2x + 8
f(x) = x(x) - x(4) + 2(x) - 2(4)
f(x) = x(x - 4) + 2(x - 4)
f(x) = (x + 2)(x - 4)
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