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What is the equation of the circle with center at (2, 4) and radius of 6?

Sagot :

the formula for the equation of a circle is

[tex](x-h) ^{2} + (y-k) ^{2} =r ^{2} [/tex]

The center (h,k) and the radius (r).
In this case the center is (2,4) so you would substitute -(h,k) with 2 and 4:

[tex](x-2) ^{2} +(y-4) ^{2} =r ^{2} [/tex]

Then just substitute for r with 6:

[tex](x-2) ^{2} + (y-4) ^{2} =6 ^{2} [/tex]

and there you go!


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