K21214idn
Answered

From personal advice to professional guidance, IDNLearn.com has the answers you seek. Join our knowledgeable community and get detailed, reliable answers to all your questions.

How do you solve x²-10x+9=0 by completing the square?

Sagot :

[tex]x^2-10x+9=0\\\\\underbrace{x^2-2x\cdot5+5^2}_{(*)}-5^2+9=0\\\\(x-5)^2-25+9=0\\\\(x-5)^2-16=0\ \ \ /+16\\\\(x-5)^2=16\iff x-5=-\sqrt{16}\ \vee\ x-5=\sqrt{16}\\\\x-5=-4\ \vee\ x-5=4\\\\x=-4+5\ \vee\ x=4+5\\\\x=1\ \vee\ x=9[/tex]



[tex](*)\ (a-b)^2=a^2-2ab+b^2[/tex]
Kate200468idn
[tex]x^2-10x+9=0 \\ \\x^2-2\cdot5x+5^2-5^2+9=0\\ \\(x-5)^2-25+9=0\\ \\(x-5)^2=16\\ \\x-5=4\ \ \vee\ \ x-5=-4\\ \\x=9\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=1[/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.