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axis of symmetry for f(x) = -2x2 + 20x -42

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RandomMammothidn
For the function [tex]f(x)=2x^2 +20x-42[/tex]

We can use the formula for the axis of symetry, which is [tex]x= \frac{-b}{2a} [/tex]

With the values substituted, we get...

[tex] \frac{-20}{2(-2)} =5[/tex]

Therefore the axis of symmetry is [tex]x=5[/tex] 

Answer: X=5

Step-by-step explanation:

i took the test on FLVS

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