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Can you explain 3x+4/5=7/10. Solve

Sagot :

Lilithidn
[tex]3x+ \frac{4}{5}= \frac{7}{10}\ \ | -\frac{4}{5}\\ \\3x+ \frac{4}{5} -\frac{4}{5}= \frac{7}{10}-\frac{4}{5}\\ \\3x = \frac{7}{10}-\frac{8}{10} \\ \\3x = -\frac{1}{10} \ \ /*\frac{1}{3}\\ \\x=-\frac{1}{30}[/tex]



[tex]or \\ \\ \frac{3x+ 4}{5}= \frac{7}{10} \ \ /*10 \\ \\ 2(3x+4)=7\\ \\6x+8 = 7\ \ |-8[/tex]

[tex]6x+8-8=7-8\\ \\6x=-1\ \ /:6 \\ \\ x=-\frac{1}{6}[/tex]


Kate200468idn
[tex]3x+ \frac{4}{5}= \frac{7}{10} \\ \\3x= \frac{7}{10}-\frac{4}{5}\\ \\3x=\frac{7}{10}-\frac{8}{10}\\ \\3x=- \frac{1}{10} \ /:3\\ \\x=-\frac{1}{10}\cdot \frac{1}{3}\\ \\x=-\frac{1}{30}[/tex]

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[tex] \frac{3x+4}{5} = \frac{7}{10} \\ \\10(3x+4)=5\cdot 7\\ \\30x+40=35\\ \\30x=35-40\\ \\30x=-5\ /:30\\ \\x=- \frac{5}{30} \\ \\x=-\frac{1}{6}[/tex]
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