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what are the coordinates of the vertex of f(x)=2x^2+4x+9

Sagot :

[tex]f(x)=2x^2+4x+9 \\ a=2 \\ b=4[/tex]

The coordinates of the vertex of a parabola are (h,k) where:
[tex]h=\frac{-b}{2a}=\frac{-4}{2 \times 2}=\frac{-4}{4}=-1 \\ \\ k=f(h)=f(-1)=2 \times (-1)^2+4 \times (-1)+9=2 -4+9=7[/tex]

The coordinates of the vertex are (-1,7).