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Write an expression for the next 3 even numbers that are greater than P
Every even number is 2 away from the last. 0, 2, 4, 6, 8, 10, 12, 14...etc.
If we had an even number p, then the next three even numbers would be p+2, p+4, and p+6.
(If we had an odd number p, then the next three even numbers would be p+1, p+3, and p+5. I'm not sure if p is even is implied in the question. Technically the answer would be p - p mod 2 + 2, where p is an interger...that gets into more technical function stuff, though.)
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