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you use a modification of the pythagorean theorem to find pythagoreas c^2=a^2+b^2 the easy way is you use the equation [tex]d= \sqrt{(x1-x2)^2+(y1-y2)^2} [/tex] so input in format (x,y) then (2,2) (7,5) x1=2 y1=2 x2=7 y2=5 [tex]d= \sqrt{(2-7)^2+(2-5)^2} [/tex] [tex]d= \sqrt{(-4)^2+(-3)^2} [/tex] [tex]d= \sqrt{16+9} [/tex] [tex]d= \sqrt{25} [/tex] [tex]d= 5 [/tex]
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