Join IDNLearn.com today and start getting the answers you've been searching for. Get step-by-step guidance for all your technical questions from our dedicated community members.
Sagot :
I don't know specifically what the sum and product of an equation is but
factor using quadratic formula
if you have an equation in ax^2+bx+c=0 then you can solve for x using
[tex]x= \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex] or [tex]x= \frac{-b- \sqrt{b^2-4ac} }{2a} [/tex]
so input
a=1
b=7
c=2
[tex]x= \frac{-7+ \sqrt{7^2-4(1)(2)} }{2(1)} [/tex]
[tex]x= \frac{-7+ \sqrt{49-8} }{2} [/tex]
[tex]x= \frac{-7+ \sqrt{41} }{2} [/tex]=aprox -0.2984378812836
[tex]x= \frac{-7- \sqrt{7^2-4(1)(2)} }{2(1)} [/tex]
[tex]x= \frac{-7- \sqrt{49-8} }{2} [/tex]
[tex]x= \frac{-7 \sqrt{41} }{2} [/tex]=aprox -6.7015621187165
factor using quadratic formula
if you have an equation in ax^2+bx+c=0 then you can solve for x using
[tex]x= \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex] or [tex]x= \frac{-b- \sqrt{b^2-4ac} }{2a} [/tex]
so input
a=1
b=7
c=2
[tex]x= \frac{-7+ \sqrt{7^2-4(1)(2)} }{2(1)} [/tex]
[tex]x= \frac{-7+ \sqrt{49-8} }{2} [/tex]
[tex]x= \frac{-7+ \sqrt{41} }{2} [/tex]=aprox -0.2984378812836
[tex]x= \frac{-7- \sqrt{7^2-4(1)(2)} }{2(1)} [/tex]
[tex]x= \frac{-7- \sqrt{49-8} }{2} [/tex]
[tex]x= \frac{-7 \sqrt{41} }{2} [/tex]=aprox -6.7015621187165
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.