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A cone has a diameter of 12 in. and a height of 16 in.

What is the volume of the cone?
Use 3.14 as an approximation for straight pi and express your final answer in hundredths.


Sagot :

TSOidn
[tex]\sf{Volume =\frac{1}{3}\times\pi\times r^2 \times h}[/tex]

diameter is 12, that means the radius or r is 6.
h is height which is 16

Plugging that in to the formula you get:

[tex]\sf{Volume =\frac{1}{3}\times\pi\times 6^2 \times 16}[/tex]

Simplify that:

[tex]\sf{Volume =\frac{1}{3}\times\pi\times 36 \times 16}[/tex]

Simplify it more:

[tex]\sf{Volume = \pi \times 12\times 16}[/tex]

Simplify it more:

[tex]\sf{Volume =\pi\times192 }[/tex]

Replace pi with 3.14 and solve

[tex]\sf{Volume = 3.14\times192 }[/tex]

Your final answer is:

[tex]\Huge{\boxed{\bf{602.88}}}[/tex]