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What is the solution to the system of equations? Using substitution method.
x=3y+5
x-4y=3
subsitution x=3y+5 x-4y=3 we know that x=3y+5 so subsitute 3y+5 for x in second equation 3y+5-4y=3 5-y=3 subtract 5 from both sides -y=-2 multiply -1 y=2
subistute 2 for y in first equationx=3y+5 x=3(2)+5 x=6+5 x=11
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