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Three angels are labeled below with arcs. The smallest angel is 3/8 as large as the 160 degree angel. Find the value of angel a 

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Kate200468idn
[tex]the\ smaller\ angle= \frac{3}{8} \cdot 160^0=\frac{3}{8} \cdot \frac{160^0}{1} = \frac{3\cdot20^0}{1} =60^0\\ \\a=360^0-(160^0+60^0)=360^0-220^0=140^0[/tex]
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