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If ƒ(x ) = 3x + 1 and and ƒ -1 = , then the ordered pair of ƒ -1(10) = (10, 31) (10, 3) (3, 10)

Sagot :

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        f(x) = 3x + 1
           y = 3x + 1
      y - 1 = 3x + 1 - 1
      y - 1 = 3x
         3       3
¹/₃y - ¹/₃ = x
           y = ¹/₃x - ¹/₃
      f⁻¹(x) = ¹/₃x - ¹/₃
    f⁻¹(10) = ¹/₃(10) - ¹/₃
    f⁻¹(10) = 3¹/₃ - ¹/₃
    f⁻¹(10) = 3
It is equal too (10, 3).
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