Bassler285idn
Answered

From simple queries to complex problems, IDNLearn.com provides reliable answers. Find accurate and detailed answers to your questions from our experienced and dedicated community members.

A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the pitcher’s hand at a velocity of 50 feet per second. If the softball’s acceleration is –16 ft/s2, which quadratic equation models the situation correctly? h(t) = at2 + vt + h0 h(t) = 50t2 – 16t + 3 h(t) = –16t2 + 50t + 3 3 = –16t2 + 50t + h0 3 = 50t2 – 16t + h0

Sagot :

Taskmastersidn
I think the correct answer from the choices listed above is the second option. The quadratic equation that would best model the system described above would be h(t) = –16t2 + 50t + 3. We can check it by looking at the resulting units.

The resulting units should be in meters.

m [=] m/s²(s²) + m/s (s) + m [=] m -----> equal

So, it should be the correct answer.

The correct answer is:

h(t) = –16t² + 50t + 3

Explanation:

The general form of an equation such as this is h(t) = at² + v₀t + h₀, where a is the constant due to gravity, v₀ is the initial velocity and h₀ is the initial height.

We are given that the constant due to gravity is -16.

The initial velocity is 50, and the initial height is 3; this gives us the equation

h(t) = -16t² + 50t + 3

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.