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simplify the expression "the square root of x^10 times the square root of x^4" completely. A. the square root of x^14 B. 2 times the square root of x^10 C. 3 times the square root of x^5 D. x^7
using the rule that √a times √b = √(a times b) √(x^10) times √(x^4) = √(x^10 times x^4) using the rule that x^a times x^b = x^(a+b) √(x^10 times x^4) = √x^(10 + 4) = √x^14 to cancel out √ with ^14, divide the number 14 by 2 (if it is ∛ then you would divide 14 by 3, and so on, but in this case it is the square root) √x^14 = x^(14/2) = x^7 so the answer is D. x^7
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