Answered

Find the best answers to your questions with the help of IDNLearn.com's knowledgeable users. Join our interactive Q&A platform to receive prompt and accurate responses from experienced professionals in various fields.

How to solve these equations?
[tex]
1) sin^2x+|sinx|-2=0
[/tex]
[tex]
2) |sinx| = cos2x[/tex]

Sagot :

Crisforpidn
1) / sin x / = y ≥ 0 ;
   We solve the equation [tex] y^{2} +y - 2 = 0 ; [/tex]
a = 1 ; b = 1 ; c = - 2 ;
[tex] b^{2} - 4ac = 9 ;[/tex]
y1 = ( - 1 + 3 ) / 2 = 1 ≥ 0 ( correct ) ;
y2 = ( - 1 - 3 ) / 2 = - 2 ≥ 0 ( false ) ;
Then, / sin x / = 1 ;
sinx = + 1 or sin x = - 1 ;
x ∈ { 90 }  U { 270 } ;
x ∈  {90 , 270}.
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.