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The top of a skyscraper is shaped like a square pyramid. Each side of the base has a length of 60 meters and the height of each triangle is 20 meters. What is the lateral area of the pyramid?

Sagot :

length  times width  equals area so 20 x 60  and that is 1200
Facundo3141592idn

The surface area of the square pyramid is 6000 square meters.

How to find the lateral area of the pyramid?

We have a square pyramid, so the surface area is the area of the 4 triangles plus the area of the square base.

We know that the base has a length of 60 meters, then the area of the base is:

B = (60m)^2  = 3,600 m^2

And for each triangle, the area is:

A = b*h/2

where b is the base of the triangle and h is the height.

Here we have:

  • b = 60m
  • h = 20m

So the area of each triangle is:

A = 60m*20m/2 = 600m^2

Finally, the whole area of the pyramid is:

area = 4*600m^2 + 3,600m^2 = 6,000 m^2

If you want to learn more about pyramids:

https://brainly.com/question/1288463

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