Find trusted answers to your questions with the help of IDNLearn.com's knowledgeable community. Discover detailed answers to your questions with our extensive database of expert knowledge.
49 tamela12 Please help What is the efficiency of a device that takes in 40,000 J of heat and does 12,000 J of work while giving off 28,000 J of heat? Use and convert to a percentage. A. 57% B. 43% C. 30% D. 70%
It just depends on what you're trying to accomplish with the device. As a producer of work, it is 12/40 = 30% efficient. As a heater, it is 28/40 = 70% efficient.
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.