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Solve. 8x + 4 ≤ –20 A. x ≥ –2 B. x ≤ –3 C. x ≥ –3 D. x ≤ –2

Sagot :

The answer to this problem: 8x+4...would be B.
[tex]8x+4 \leq - 20 \\ subtract\ 4 \\ 8x \leq -24 \\ divide\ by\ 8\\ \boxed{x \leq -3}[/tex]