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Maria will spin the arrow on the spinner 3 times.
What is the probability that the arrow will stop on A, then B, then C?

A. 3/256
B. 1/64
C. 1/12
D. 3/4

Sagot :

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Well if those are the only 3 options of a segment, then there is a 1/3 chance of landing on A, then a 1/3 chance of landing on B, then a 1/3 chance of landing on C. Multiply the fractions together to get 1/27. However that isn't one of your answers. I'm thinking that the spinner has 4 sections, meaning 1/4 chance of A, then 1/4 chance of B, then 1/4 chance of C. Multiply these together to get 1/64, which is one of your answers. That's my input anyway
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