Answered

Find the best solutions to your problems with the help of IDNLearn.com's experts. Ask anything and receive prompt, well-informed answers from our community of experienced experts.

Please help my friend cant figure this out [tex]1/y+9 -2=1/2(y+9) [/tex]
The 1/y+9 is 1
_____
y+9

Sagot :

Apologiabiologyidn
I don't know, I will solve for y
1/y+9-2 is 1 so that prpbably means parenthasees
(1/y+9)-2=1/2 times (y+9)
multiply both sides by 2
2(1/y+9)-4=y+9
add 4 to both sides
2(1/y+9)=y+13
distribute
2/y+18=y+13
subtract 13 from both sides
2/y+5=y
multily both sides by y
2+5y=y^2
subtract 2+5y from both sides
y^2-5y-2=0
if we can factor then assume
if you can factor equation into zy=0 then assume z or/and y=0 so 
use quadratic formula 
in ay^2+by+c=0 then 
y=[tex] \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex] or [tex] \frac{-b- \sqrt{b^2-4ac} }{2a} [/tex]

so subsitute and get 
y= [tex] \frac{5+ \sqrt{33} }{2} [/tex] or [tex] \frac{5- \sqrt{33} }{2} [/tex] 
2(¹/y+9)-4=y+9
2/y+18=y+9+4
2/y+18=y+13
2/y+[18-13]=y
2/y+5=y
2+5y=y²
y²-5y-2


Y=-b±√b²-4ac
------------------
2a

y=5±√25-4•1•-2
---------------
2

Y=[5+√33]/2


Y=[5-√33]/2

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.