Answered

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12 people are standing in line to buy movie tickets. The theater is running a promotion by giving away 2 concession stand gift cards to the people standing in line.

What is the probability that the 2nd and 3rd people in line will get chosen for the gift cards?

Sagot :

IwAsSoMeGuYidn
1 in 12 chance of second person getting given a ticket
Then a 1 in 11 chance of the third person being given one.
1/12*1/11 = 1/132 chance. However, if it doesn't have to be in order, then there's a 1/12 chance of the third person getting a ticket, then a 1/11 chance of the second person getting one, so another 1/132 chance. Add them together for 2/132, or 1/66 chance
Amattimoeidn
can you clarify, please. do you mean every 2nd and 3rd person?

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