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Find two mixed numbers so that the sum is 7 2/8 and the difference is 2 4/8.
Well let's call the smaller of the numbers n We know that n + (n + 2 4/8) = 7 2/8 In simpler form, 2n + 2 4/8 = 7 2/8 Subtract 2 4/8 from both sides to get 2n = 4 6/8 Divide both sides by 2 to isolate n, so n = 2 3/8 To find the larger number, add 2 4/8 to the smaller number, getting 4 7/8
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