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If an element, X, can form an oxide that has theformula X2O3, then element X would most likely be located on the Periodic Table in the same group as
(1) Ba (3) In
(2) Cd (4) Na

Sagot :

In! This is becasue it has a valency of 3

Answer: (3) In

Explanation: As the given compound is [tex]X_2O_3[/tex], it can be said that X has a valency of 3.

1)Barium (Ba): Atomic no: 56: [tex]Xe6s^2[/tex] : In order to complete its octet, it needs to donate 2 electrons, and thus the valency is 2.

2) Cadmium (Cd) : Atomic no: 48: [tex]Kr5s^24d^{10}[/tex] : In order to complete its octet, it needs to donate 2 electrons, and thus the valency is 2.

3) Indium (In): Atomic no: 49: [tex]Kr5s^25p^{1}[/tex] : In order to complete its octet, it needs to donate 3 electrons, and thus the valency is 3.

4) Sodium (Na): Atomic no: 11: [tex]Ne3s^1[/tex] : In order to complete its octet, it needs to donate 1 electron, and thus the valency is 1.

So the given element could only belong to the group containing Indium (In) as all the elements in the same group exhibit similar valency.

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