IDNLearn.com makes it easy to find answers and share knowledge with others. Get accurate and timely answers to your queries from our extensive network of experienced professionals.
What is the total amount of heat absorbed by 100.0 grams of water when the temperature of the water is increased from 30.0°C to 45.0°C?
(1) 418 J (3) 12 500 J
(2) 6270 J (4) 18 800 J
The total amount of heat is the same as the energy. Because no phase change is occurring, use the formula Q = mc(delta)T. Q is the energy, m is the mass, c is the specific heat capacity of water as a liquid, and (delta)T is the change in temperature. So: Q = (100.0 g)(4.186 J/g°C)(15°C); Q = 6279 Joules.
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.