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Raymond ran "x" miles on Tuesday. On Wednesday, he ran twice as far, but, on Thursday he only ran 1/2 Tuesday's distance. If Raymond ran a total of 9 miles on three days, how far did he run each day?

Sagot :

A386idn
Tuesday=[tex]x[/tex]
Wednesday=[tex]2x[/tex]
Thursday=[tex] \frac{1}{2} x[/tex]

[tex]x+2x+ \frac{1}{2} x=9 \\ \frac{7}{2}x=9 \\ \frac{7}{2}x*2=9 *2\\ 7x=18\\ \frac{7}{7} x=\frac{18}{7}\\ x=\frac{18}{7}[/tex]

Remember that the x value is only for Tuesday's distance; therefore:

Tuesday= [tex] \frac{18}{7} [/tex]miles
Wednesday= [tex] \frac{36}{7} [/tex]miles
Thursday= [tex]\frac{9}{7}[/tex]miles
Vaeh1234idn
The equation would be x+2x+1/2x=9 miles. Add all the like terms. x+2x=3x. 3x+1/2x= 3 1/2x. So 3 1/2x=9.
Then you would have to do 3 1/2x divided by 3 1/2 which would equal x. Then, 9 divided by 3 1/2 which would equal about 2.57....not completely sure but try it...
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