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An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is the approximate percent error?
The experiment result shows that the density of CO2 at STP is 0.1/0.056=1.79 g/L. The percent error equals: |1.79-1.96|/1.96*100%=8.67%. So the answer is 8.67%.
The experimental density is calculated as: [tex]\frac{0.10}{0.056} = 1.79[/tex] g/L. To calculate the percent error, we use the equation: [tex]\frac{|Experimental-Theoretical|}{Theoretical}=\frac{|1.79-1.96|}{1.96}=0.0889[/tex] Therefore, the % error is 8.89%
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