DelmaDecillis4idn
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The percentage by mass of Br in the compound
AlBr3 is closest to
(1) 10.% (3) 75%
(2) 25% (4) 90.%

Sagot :

What you have to do it find the percentage / solve it. Divide the mass by the entire mass. 
239.7 ÷ 266.68 = 0.898 × 100 = 90% Br.

Answer: The correct answer is option(4).

Explanation:

Molar mass of the aluminium bromide, [tex]AlBr_3=266.69 g/mol[/tex]

Atomic mass of bromine = 79.90 g/mol

Percentage of Mass of bromine in [tex]AlBr_3[/tex]:

[tex]\% Br\text{ by mass}=\frac{\text{Atomic mass of Br}\times \text{Number of Br atoms}\times 100}{\text{Molar mass of }AlBr_3}[/tex]

[tex]\% Br\text{ by mass}=\frac{79.90 g/mol\times 3\times 100}{266.69 g/mol}=89.97\%\approx 90\%[/tex]

Hence, the correct answer is option(4).

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