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how many bricks 3.75 in. Wide × 8 in. Long are required to cover a patio 13 ft. 6 in. Wide by 18 ft 9 in. Long ?

Step 1. First, find the total width & length of the patio in inches.

Step 1a. Convert the portion of width and length that is expressed in feet to inches.

Width: 13 ft = 13 × ___ = ___in

Length: 18 ft = 18 × ____ = _____ in

Sagot :

Jaleahalvarez18idn
Ab = (3.75/12)*(8/12) = 0.20833333 ft^2. 
= Area of each brick. 

Ap = 18.75 * 13.5 = 253.125 Ft^2. = 
Area of patio. 

Bricks = Ap/Ab = 253.125/0.20833=1215. 

Answer:

1215 bricks will be required.

Step-by-step explanation:

Length of a brick L= 8 in. and width of the brick w = 3.75 in.

Area of one brick = 8×3.75 = 30 in²

Now length of a patio = 13 feet 6 in

since 1 feet = 12 inch.

So length of the patio = (13×12 + 6)= 162 in

Similarly width of the patio = 18 feet 9 inch = (18×12 + 9) = 216 + 9 = 225 inch

Area of the patio = 162×225 = 36450 in²

Now total bricks required to cover patio = Area of patio ÷ area of one brick

                                                                   = 36450 ÷ 30 = 1215 bricks

Therefore 1215 bricks will be required to cover a patio.

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