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if the perimeter of the rectangle is 48, find the dimensions
p=perimeter l=legnth w=width so perimiter of rectangle=legnth+legnth+width+widht or p=2l+2w or undistribute the 2 p=2(l+w) if p=48 then 48=2(l+w) divide by 2 24=l+w so the answer is l+w=24 l=24-w w=l-24 subsitue legnth>width answeres could be: L,W 23,1 22,2 21,3 20,4 19,5 18,6 17,7 16,8 15,9 14,10 13,11 and that is only the integer pairs
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