Get clear, concise, and accurate answers to your questions on IDNLearn.com. Get the information you need from our community of experts who provide accurate and thorough answers to all your questions.
A gas occupies a volume of 444 mL at 273 K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure is changed to 38.7 kPa?
(1) 31.5 K (3) 566 K(2) 292 K (4) 2360 K
The answer is (3) 566 K. For this problem, you need the combined gas law, which is P1V1/T1 = P2V2/T2 (variables represent Pressure, Volume, and Temperature). You are looking for T2, so you get T2 = P2V2T1/P1V1 = (38.7)(1880)(273)/(79.0)(444) = 566 K.
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.
