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A gas occupies a volume of 444 mL at 273 K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure is changed to 38.7 kPa?
(1) 31.5 K (3) 566 K(2) 292 K (4) 2360 K
The answer is (3) 566 K. For this problem, you need the combined gas law, which is P1V1/T1 = P2V2/T2 (variables represent Pressure, Volume, and Temperature). You are looking for T2, so you get T2 = P2V2T1/P1V1 = (38.7)(1880)(273)/(79.0)(444) = 566 K.
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