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The balanced equation below represents the decomposition of potassium chlorate.
2KClO3(s) → 2KCl(s) + 3O2(g)
Determine the oxidation number of chlorine in the reactant in the equation.
State why the entropy of the reactant is less than the entropy of the products.
The oxidation number of chlorine in the reactant can be determined by K ion and O ion. K ion is +1 and O ion is -2. And the Cl is +5. The gas has the greatest entropy and the solid has the least. In the production, there are solid and gas. So it has more entropy than the reactants with solid only.
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