IDNLearn.com: Your one-stop platform for getting reliable answers to any question. Our experts are ready to provide in-depth answers and practical solutions to any questions you may have.
How much iron is present in 4.64 g of iron(iii) oxide? answer in units of g
The formula of iron(iii) oxide is Fe2O3. The gram formula mass of Fe2O3 is 56*2+16*3=160. And the Fe accounts for 56*2=116 in one molecule. So the iron mass is 4.64/160*116=3.364 g.
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.
