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How much iron is present in 4.64 g of iron(iii) oxide? answer in units of g
The formula of iron(iii) oxide is Fe2O3. The gram formula mass of Fe2O3 is 56*2+16*3=160. And the Fe accounts for 56*2=116 in one molecule. So the iron mass is 4.64/160*116=3.364 g.
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