CanadaWidn
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Solving for systems:

{y=3x+7 &     y=5x-7



Sagot :

[tex]\left\{\begin{array}{ccc}y=3x+7\\y=5x-7\end{array}\right\\\\substitute:\\\\5x-7=3x+7\\5x-3x=7+7\\2x=14\ \ \ \ /:2\\x=7\\\\y=3\cdot7+7=21+7=28\\\\Answer:x=7\ and\ y=28.[/tex]
Tadvisohil886idn
y = 3x + 7
y = 5x-7

Now, we know that y = y

thus,

3x + 7 = 5x-7
3x - 5x = -7 -7

= -2x = -14

thus, -x = -14/-2

thus, x = 7.

Substituting for y,

y = 3x + 7
= 3 x 7  + 7

= 28.

Thus, x = 7, y =28
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