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Cao(s) + h2o(l) = ca(oh)2(s) what mass of slaked lime can be produced from a mixture of 28.4 g of cao and 13.3g of h20
The equation given is already balanced. The mol number of CaO is 28.4/56=0.51 mol. The mol number of H2O is 13.3/18=0.74 mol. So the slaked lime being produced is 0.51 mol equals to 37.74 g.
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