ToddDebiasioidn
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Noj has the following test scores:
76, 84, 69, 74, 91
His teacher will allow him to retake the test on which he scored lowest. Noj wants an average of
at least 82. Determine the least number of additional points Noj must score on the retest.

Sagot :

Apologiabiologyidn
so the test he scored lowest is 69 so discard this score and put x for it average=numbers added together then summ is divided by number of numbers exg average of 2 and 4 and 5 is 2+4+5=11 then 3 numbers so 11/3 is average or aprox 3 and 2/3 so [tex] \frac{76+84+x+74+91}{5} [/tex]=average he wants his new average to be at least 82 so [tex] \frac{76+84+x+74+91}{5} \geq 82 [/tex] solve [tex] \frac{76+84+x+74+91}{5} \geq 82 [/tex] treat as equation first add like terms in top [tex] \frac{325+x}{5} \geq 82 [/tex] multiply both sides by 5 to clear fraction 325+x [tex] \geq [/tex] 410 subtract 325 from both sides x [tex] \geq [/tex] 85 he must get [tex] \geq [/tex] 85 to get an average of at least 82

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