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Sagot :
[tex]3m^2n+12mn^2[/tex]
In both the sets, 3 and m as well as n can be found as common factors.
So,
3mn( m+4n)
Therefore the answer is 3mn (#3)
In both the sets, 3 and m as well as n can be found as common factors.
So,
3mn( m+4n)
Therefore the answer is 3mn (#3)
3m²n + 12mn²
3mn(m) + 3mn(4n)
3mn(m + 4n)
The GCF of 3m²n + 12mn² is 3mn.
3mn(m) + 3mn(4n)
3mn(m + 4n)
The GCF of 3m²n + 12mn² is 3mn.
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