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What is the change in temperature if 24g of water at 50°C absorbs 985 J of heat energy?



Sagot :

Astonkute8idn
The formula is q=M*C*(Change in T)
q= 985 J
M= 24g
C= 4.186 j/gram (it's waters specific heat) 
Change in T= X (unknown) 

Once you solve for X, you should get 9.8, at least that's what I got. 
So the change in temperature is 9.8 C. 
Sebassandinidn

Answer:

[tex]\Delta T=9.82^oC[/tex]

Explanation:

Hello,

In this case, we consider such heat absorption as an energy inlet, that is why the temperature of the water will raise as shown below as a positive result is obtained, considering water's heat capacity as 4.18 J/(g*°C):

[tex]Q=mCp\Delta T\\\Delta T=\frac{Q}{mCp}=\frac{985J}{24g*4.18\frac{J}{g^oC} }\\\\\Delta T=9.82^oC[/tex]

Best regards.

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