Get expert advice and community support on IDNLearn.com. Get comprehensive answers to all your questions from our network of experienced experts.

How many grams of NH3 can be produced from 2.27mol of N2 and excess H2.

Sagot :

The reaction formula of this is N2 + 3H2 = 2NH3. So the ratio of mol number of N2 and NH3 is 1:2. The mol number of NH3 is 2.27*2=4.54 mol. So the mass is 4.54*17=77.18 g.