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PLEASE Find the equation of the line............................perpendicular to the line y= 5x -1 and passes through the points (10,8)
Since it's perpendicular to the line with the slope 5, you take the reciprocal of 5 which is 1/5 and change the sign: -1/5. So you have the equation: y=-(1/5)+b. To find b you substitute x and y for the coordinate (10,8). y=(-1/5)x+b 8=(-1/5)10+b 8=(-10/5)+b 8=-2+b +2 +2 10=b
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