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recall that the length a spring streches varies directly with the amount of weight attached to it. a certain spring stretches 5cm when a 10-gram weight is attached write a direct variation equation relating the weight x and the amount of stretch y.
In this case, y=1/2x. The spring stretches 5 cm for every 10 grams. Therefore if y=5 and x=10, k would have to be 1/2. That's how we come up with our direct variation model.
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