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a particle moves along the x axis. Its position as a function of time is given by x= 4.8t 7.3 t^2, where t is in seconds and x is in meters. What is the acceleration as a function of time?

Sagot :

MathPhysidn

Answer:

x'' = 14.6

Explanation:

The acceleration of the particle is equal to the second derivative of its position function.

The position function is:

x = 4.8t + 7.3t²

The first derivative is:

x' = 4.8 + 14.6t

The second derivative is:

x'' = 14.6

Therefore, the acceleration is constant at 14.6 m/s².

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