Answer:
12 days
Step-by-step explanation:
Let m be number of machines, R be rate of hour /day that the machines work and D be number of days.
It is inferred that m is proportional to R and inversely proportional to D
[tex] \: m = \frac{kR }{ D } [/tex]
k = mD / R, when. m = 18, D = 5 and R = 6
k = (18 × 5) / 6
k = 3 × 5
k = 15
Therefore,
[tex] \: m = \frac{15R }{ D } [/tex]
is the equation connecting the three parameters together.
D = ? when m = 10 and R = 8
[tex] \:D = \frac{15R }{ m} [/tex]
= (15 × 8) / 10
= (3 × 8) / 2
= 3 × 4
= 12.
Hence,
It will take 12 days for 10 machine a to do same work.
