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Sagot :
Let's carefully translate the real-world situation into an algebraic equation step by step.
1. Identify the known values:
- Your mom gives you [tex]$50 to spend. - The price of apples is $[/tex]2.50 per pound (p).
2. Determine the relationship:
- The total amount of money you have is [tex]$50, which is constant. - The cost of buying 'p' pounds of apples at $[/tex]2.50 per pound is given by the expression [tex]\(2.50p\)[/tex].
3. Set up the equation:
- The money spent on apples plus any remaining money must equal the total money you started with, which is $50.
- The remaining money you have after buying apples can be expressed as [tex]\(50 - 2.50p\)[/tex].
4. Form the algebraic equation:
- To express the remaining money after spending, the final equation is:
[tex]\[ 50 - 2.50p \][/tex]
Thus, the algebraic equation representing the relationship is:
[tex]\[ 50 - 2.50p \][/tex]
1. Identify the known values:
- Your mom gives you [tex]$50 to spend. - The price of apples is $[/tex]2.50 per pound (p).
2. Determine the relationship:
- The total amount of money you have is [tex]$50, which is constant. - The cost of buying 'p' pounds of apples at $[/tex]2.50 per pound is given by the expression [tex]\(2.50p\)[/tex].
3. Set up the equation:
- The money spent on apples plus any remaining money must equal the total money you started with, which is $50.
- The remaining money you have after buying apples can be expressed as [tex]\(50 - 2.50p\)[/tex].
4. Form the algebraic equation:
- To express the remaining money after spending, the final equation is:
[tex]\[ 50 - 2.50p \][/tex]
Thus, the algebraic equation representing the relationship is:
[tex]\[ 50 - 2.50p \][/tex]
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