Connect with a global community of knowledgeable individuals on IDNLearn.com. Ask anything and receive well-informed answers from our community of experienced professionals.

determines the amount of energy given off for a specific temperature

Sagot :

Answer:

You're referring to the Stefan-Boltzmann law!

The Stefan-Boltzmann law is a fundamental concept in physics that relates the total energy radiated by a blackbody (an idealized object that absorbs all incoming radiation) to its temperature. The law states that the total energy emitted by a blackbody is proportional to the fourth power of its temperature.

Mathematically, the law can be expressed as:

E = σ \* T^4

Where:

* E is the total energy emitted by the blackbody (in watts per square meter)

* σ is the Stefan-Boltzmann constant (approximately 5.67 × 10^-8 W/m²K⁴)

* T is the temperature of the blackbody (in Kelvin)

This means that as the temperature of a blackbody increases, the energy it emits also increases exponentially. For example, if you double the temperature of a blackbody, its energy output will increase by a factor of 16 (2^4).

To calculate the amount of energy given off for a specific temperature, you can plug in the desired temperature value into the equation above. For example:

* If you want to find the energy emitted by a blackbody at a temperature of 500 K (227°C or 440°F), you would plug in T = 500 K into the equation:

E = σ \* (500 K)^4

= 5.67 × 10^-8 W/m²K⁴ \* (500 K)^4

= approximately 1.42 × 10^5 W/m²

So, a blackbody at a temperature of 500 K would emit approximately 1.42 × 10^5 watts per square meter.

Keep in mind that this is a simplified calculation, and real-world objects do not always behave as perfect blackbodies. However, the Stefan-Boltzmann law provides a useful estimate of the energy emitted by an object at a given temperature.

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.