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Find the perimeter and the area of the rectangle with length of (2x-7) and width of (-3x-4)

Sagot :

Answer:

The perimeter is (-2x-22) and the area is [tex]-6x^2+13x+28[/tex].

Step-by-step explanation:

Perimeter & Area

Perimeter

Perimeter is the sum of all the side lengths of a given shape. In our case, for a rectangle, the perimeter is the sum of twice its length and twice its width or,

                                            [tex]P=2(l+w)[/tex].

Area

The area of a rectangle is the product of its length and width or,

                                                 [tex]A=lw[/tex].

Applying the Formulas

Perimeter

We're given the rectangle's length and width, all we have to do it plug them into the perimeter formula stated above!

[tex]P=2(l+w)=2[\:(2x-7) \:+(-3x-4)\:][/tex]

[tex]=2[-x-11]\\\\\Longrightarrow P=-2x-22[/tex].

Area

We plug in the known value of l and w into the area formula, similarly to how we did it to calculate perimeter.

[tex]A=lw=(2x-7)(-3x-4)[/tex]

[tex]=-6x^2-8x+21x+28\\\\\Longrightarrow A = -6x^2+13x+28[/tex].