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A soufflé increases in height by 125% while in the oven. If the finished height is 13.5 cm, how tall was the soufflé before it was put in the oven?
To determine the initial height of the soufflé before it was put in the oven, we can follow these steps:
1. Understand the percentage increase: A 125% increase in height means that the soufflé becomes 125% taller than its original height. This is equivalent to an increase factor of [tex]\(1.25\)[/tex].
2. Define the variables: Let's denote the initial height of the soufflé as [tex]\( h \)[/tex]. The final height of the soufflé, after it has risen in the oven, is given as 13.5 cm.
3. Establish the relationship: Given that the soufflé increases by 125%, the final height can be expressed as: [tex]\[
h + 1.25h = 13.5 \, \text{cm}
\][/tex] This simplifies to: [tex]\[
2.25h = 13.5 \, \text{cm}
\][/tex]
4. Solve for the initial height [tex]\( h \)[/tex]: [tex]\[
h = \frac{13.5 \, \text{cm}}{2.25}
\][/tex] [tex]\[
h = 6.0 \, \text{cm}
\][/tex]
Therefore, the initial height of the soufflé before it was put in the oven was 6.0 cm.
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